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Q. A sum of  â‚¹90 is distributed amongst A, B and C in such a way that A gets  â‚¹2 more than B and B gets  â‚¹2 more than C. The share of A is(A)  â‚¹28 (B) â‚¹30(C)  â‚¹32 (D)  â‚¹34

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Q. A sum of  â‚¹90 is distributed amongst A, B and C in such a way that A gets  â‚¹2 more than B and B gets  â‚¹2 more than C. The share of A is

(ADRE 2024)

(A)  â‚¹28

(B) â‚¹30

(C)  â‚¹32

(D)  â‚¹34

Answer:- (C)  â‚¹32

Solution:- 

Let C’s share be x.
Then, B’s share = x + 2
And, A’s share = x + 2 + 2 = x + 4

According to the problem,
⇒ x + (x + 2) + (x + 4) = 90
⇒ 3x + 6 = 90
⇒ 3x = 90 – 6
⇒ 3x = 84
⇒ x = 84 / 3
⇒ x = 28

So, A’s share = x + 4 = 28 + 4 = 32


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