Q. 10 Coins, Each Having Circular Surface Area Of 24 Cm2 And Thickness Of 2 Mm, Are Stacked One Over The Other. The Volume Occupied By The Stack Is

Before solving this problem, let’s first define what is a stack. A stack refers to a pile of coins placed one on top of the other. When we stack the coins, we align them vertically, forming a cylinder-shaped column with a combined height equal to the total thickness of all the coins together.

To find the volume occupied by the stack, we need to calculate the volume of one coin and then multiply by the total number of coins.

The volume of a cylinder (coin) is given by: Volume of one coin=Area of circular surface × thickness

In the example it was given that:

Area of circular surface = 24 cm²

Thickness (height) of each coin = 2 mm = 0.2 cm

Number of coins = 10

Calculation of the total volume

To find the volume occupied by the stack, we need to calculate the volume of one coin and then multiply by the total number of coins.

The volume of a cylinder (coin) is given by:

Volume of one coin=Area of circular surface×thickness

$So, the volume of one coin = 24 cm 2 \times 0.2 cm = 4.8 cm 3$

So, the total volume for 10 coins: Total volume=4.8cm $3$ ×10=48cm $3$

So, the answer is (A) 48 cm³

Q. 10 coins, each having circular surface area of 24 cm2 and thickness of 2 mm, are stacked one over the other. The volume occupied by the stack is

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